Forum Home
Press F1
 
Thread ID: 65989 2006-02-07 05:28:00 PHP Update problem with "-" symbol Morgenmuffel (187) Press F1
Post ID Timestamp Content User
427907 2006-02-07 05:28:00 Hi all

A number is being returned as "454776-01" (which is correct) and when I echo the number out it echos out as "454776-01", BUT when i write it to the database it gets written in as "454776" everything after the "-" symbol is lost
and I can't work out how to prevent it losing the data
the field in the database is a varchar(50) so that shouldn't be a problem

If i can echo out the returned number, then i should be able to write it to the database shouldn't I?

$bob = $ti;
echo $bob.'<br>'; this echos out as 454776-01

mysql_query("update a_orders
set error_code = ".$ec.",
transaction_Id = ".$bob."
where order_Id = '".$merchant_ref."'
AND merchant_session = '".$ms."'");

Thanks
Morgenmuffel (187)
427908 2006-02-07 05:57:00 Doesn't transaction_Id's value $bob need to be quoted as well just like you do in the ... where order_Id = '".$merchant_ref."' part?? Otherwise MySQL is thinking it is a number of sorts.

I'd just write code like:

$sql = "update a_orders
set error_code = ".$ec.",
transaction_Id = ".$bob."
where order_Id = '".$merchant_ref."'
AND merchant_session = '".$ms."'";

and echo that to what sql query that MySQL is getting.

You want to quote with a function like this (nz.php.net) . Or use PEAR DB abstraction layer or something.
gibler (49)
427909 2006-02-07 09:37:00 Doesn't transaction_Id's value $bob need to be quoted as well just like you do in the ...where order_Id = '".$merchant_ref."' part?? Otherwise MySQL is thinking it is a number of sorts.


Exactly right

Thanks Gibler

this is the second time in as many days as i have missed the obvious,

thank god the school holidays finish tomorrow, i'll be able to work without bored kids, tv and the barbie website chattering on in one ear
Morgenmuffel (187)
1