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| Thread ID: 77685 | 2007-03-18 18:07:00 | Formula To Convert To Drive Size? | SurferJoe46 (51) | Press F1 |
| Post ID | Timestamp | Content | User | ||
| 534096 | 2007-03-18 18:07:00 | If one knows the number of CYLINDERS, HEADS & SECTORS, can the size of the drive in GIG's be computed? If so, try this out and help me figger out what I've got here... CYLINDERS = 16283 HEADS= 16 SECTORS= 63 I suspect this is about 8.4 GIG...does that compute? No other details or labels are on the drive anywhere. It is a Maxtor, however. |
SurferJoe46 (51) | ||
| 534097 | 2007-03-18 20:02:00 | It would be if your hard disk controller doesn't support Logical Block Addressing. From the same guide that I said had all the answers "all drives over 8.4 GB have logical geometry parameters of 16,383 cylinders, 16 heads and 63 sectors, which is why these drives show up as being about 8.4 GB in size if Int13h extensions have not been implemented." www.storagereview.com |
PaulD (232) | ||
| 534098 | 2007-03-18 20:19:00 | If one knows the number of CYLINDERS, HEADS & SECTORS, can the size of the drive in GIG's be computed? If so, try this out and help me figger out what I've got here... CYLINDERS = 16283 HEADS= 16 SECTORS= 63 I suspect this is about 8.4 GIG...does that compute? No other details or labels are on the drive anywhere. It is a Maxtor, however. For what it’s worth Joe I just use (cylinders x heads x sectors x 512) / 1024 to give Kb’s and you can take it from there to calculate Meg’s Gig’s etc. I’d call it 8.2 gig but a lot depends whether you call a Kb 1000 bytes or 1024 bytes. ;) |
B.M. (505) | ||
| 534099 | 2007-03-18 22:00:00 | Sweet...thanks for that help...there's always someone who has an answer. | SurferJoe46 (51) | ||
| 534100 | 2007-03-19 09:40:00 | These don't have rigidly defined sizes any more. They used to have meaning but you shouldn't need to deal with them at all nowadays except maybe if you happen to work on high performance databases. | TGoddard (7263) | ||
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