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Thread ID: 78736 2007-04-26 23:13:00 Install blocker plod (107) Press F1
Post ID Timestamp Content User
544563 2007-04-26 23:13:00 does anybody have any experience with this program or a work around for it.
I have a legit reason to try and break it.
plod (107)
544564 2007-04-26 23:15:00 What is it? Speedy Gonzales (78)
544565 2007-04-27 01:34:00 Sorry. It's a program that stops you installing software/restricts the machine.
You need a password for it.
To cut a long story short, This program was installed onto a company computer by the supplier and everytime you need to add a program or make system changes you have to ring there technician to come out.
This involves a certain church(sect).
plod (107)
544566 2007-04-27 01:38:00 Well, I would say the company put it there for a reason.

And unless you own the company or the PC's its installed on, I wouldnt post in here asking how to bypass it.
Speedy Gonzales (78)
544567 2007-04-27 01:50:00 Tried something as simple as removing it from startup and disabling any associated services? Metla (12)
544568 2007-04-27 01:58:00 Well, I would say the company put it there for a reason.

And unless you own the company or the PC's its installed on, I wouldnt post in here asking how to bypass it.
No i don't own the company, but the people that do have asked me to have a look for them. It's about the church limiting them on what they can run on there own computers. company owns the computers not the church.
Thanks Metla will give it a try.
plod (107)
544569 2007-04-27 02:01:00 Why did the company purchase computers with this limitation in the first place? DeSade (984)
544570 2007-04-27 02:10:00 thats the only way they could purchase them was through there church. Otherwise not allowed computers.
Can anybody guess what church yet?
plod (107)
544571 2007-04-27 02:20:00 Its not hard to guess and that in itself is reason enough to break it.
I don't have the expertise but I wish you luck.
DeSade (984)
544572 2007-04-27 02:30:00 Perhaps prayer would bring o enlightenment from on high. Or not. Graham L (2)
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