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Thread ID: 62999 2005-10-26 03:51:00 Maths Integration Whiz's Anyone Veale (536) PC World Chat
Post ID Timestamp Content User
399421 2005-10-26 03:51:00 Is anyone here an integration expert and willing to assist me with some integration problems?

Cheers

Veale
Veale (536)
399422 2005-10-26 04:28:00 post the full question Prescott (11)
399423 2005-10-26 08:58:00 Fire away. Have you checked out Studyit (http://www.studyit.org.nz) yet?

Cheers :)
Renmoo (66)
399424 2005-10-26 10:21:00 university maths is there for one reason, bashing differentiation and integration into your head.

Post the question and I'll see what I can do.
DangerousDave (697)
399425 2005-10-26 19:36:00 1)A body is thrown out horizontally at 15m/s from a 50m high cliff on Mars where the acceleration due to gravity is -3.70m/s/s. Ignoring any drag,
Find:
i) the velocity after 1s
ii) the height above the cliff base after 1s
iii) when the body hits the ground
iv) how far horizontally from the cliff the body travels


2) Find the area enclosed by a half cycle of y=5sin(3t) and the t axis

Cheers

Veale
Veale (536)
399426 2005-10-26 22:49:00 The first problem doesn't appear to involve integration, only standard physics equations for an accerating body and constant velocity (the horizontal component). Are you wanting us to do your homework for you?

The second is an integration problem but it is too long ago since high school maths...
user (1404)
399427 2005-10-26 22:58:00 The first question needs to be done by integration.

Yes this is homework, but after failing Maths 1b twice (3rd time lucky??) im grasping at straws to pass. One paper buggering up my whole course doesn't bode well with me. If helping with homework does not prick your conscience i am in desperate need of anyones assistance.

Thanks in anticipation.
Veale (536)
399428 2005-10-27 00:06:00 The first question is based on plane motion of a projectile in cartesian coordinates, and is a special case of the more general one of firing a projectile such as a shell from a gun.

horizontal velocity dx/dt=u. x=horizontal axis, t=time, u=horizontal velocity

hence by integrating x=ut

d²y/dt²=-a y=vertical axis, a=acceleration

hence by integration, y=-at²

so eliminating t, y=-ax²/u², a parabola.

It is now left as an exercise for the reader to complete the rest of the calculations :)


The second question is based on finding what a half cycle means ie when
3t=π (thats meant to be pi.), ie integrate between t=0 and t=π/3

In general ∫sinAt= -1/A∫cosAt

So again it is left as an exercise to complete the calc.
Terry Porritt (14)
399429 2005-10-27 00:27:00 Uh huh, thats what the tuition notes read . Tuition notes do not provide answers, just like your reply!

A proper answer would be preferable .
Veale (536)
399430 2005-10-27 00:50:00 Uh huh, thats what the tuition notes read . Tuition notes do not provide answers, just like your reply!
A proper answer would be preferable .

Providing you with the answer won't help you pass your course at the 3rd attempt .

Better by far you take the time and make the effort to do this yourself, otherwise if you meet a similar problem/equation in your next exam you will be stuffed .

Cheers

Billy 8-{)
Billy T (70)
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