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| Thread ID: 88544 | 2008-03-31 08:27:00 | Solving x^5 equation | Renmoo (66) | PC World Chat |
| Post ID | Timestamp | Content | User | ||
| 654570 | 2008-03-31 08:27:00 | Dear all, Can someone with a (super?) graphics calculator please find the 5 values for "y" for the equation below? (1.13 x 10^-4)(y^5) + (3.4352 x 10^-5)(y^4) + y - 0.912 = 0 Alternatively, if you know of a website where degree of "5" equations can be solved, please let me know. Cheers :) |
Renmoo (66) | ||
| 654571 | 2008-03-31 08:58:00 | let me have a lil try..... hmmmmm...... still working it out llol... | password (5384) | ||
| 654572 | 2008-03-31 09:12:00 | Let me take it into my math teacher tomorrow, he is a genius!! Whan do you need the answer for? | password (5384) | ||
| 654573 | 2008-03-31 09:16:00 | Mathomatic (http://www.mathomatic.org/) can probably solve it, if you can be bothered learning how to use it. | Erayd (23) | ||
| 654574 | 2008-03-31 09:53:00 | Let me take it into my math teacher tomorrow, he is a genius!! Whan do you need the answer for? To find the pH :p [Edit] Just realised that it is called a quintic equation. A calculator has been found here: firstyear.chem.usyd.edu.au Cheers :) |
Renmoo (66) | ||
| 654575 | 2008-03-31 11:17:00 | I can't help with the problem, but I have a suggestion... when you're quoting numbers in an equation or even in text, it's probably a good idea to use the text version of a number where you're asking for a quantity. For example your question: Can someone with a (super?) graphics calculator please find the 5 values for "y" for the equation below? (1.13 x 10^-4)(y^5) + (3.4352 x 10^-5)(y^4) + y - 0.912 = 0 Would be better written: Can someone with a (super?) graphics calculator please find the five values for "y" for the equation below? (1.13 x 10^-4)(y^5) + (3.4352 x 10^-5)(y^4) + y - 0.912 = 0 |
Greg (193) | ||
| 654576 | 2008-03-31 18:04:00 | so you have worked it out?? | password (5384) | ||
| 654577 | 2008-03-31 18:49:00 | According to my "roots" solving routine the answer is: -7.1523 + 6.8670i -7.1523 - 6.8670i 6.5443 + 6.8700i 6.5443 - 6.8700i 0.9119 The first four are complex roots. There is only one real root. |
TideMan (4279) | ||
| 654578 | 2008-03-31 20:10:00 | According to my "roots" solving routine the answer is: -7.1523 + 6.8670i -7.1523 - 6.8670i 6.5443 + 6.8700i 6.5443 - 6.8700i 0.9119 The first four are complex roots. There is only one real root. There's no answer to that! :blush: |
Richard (739) | ||
| 654579 | 2008-03-31 21:32:00 | I have worked it out. Greg: Yup, I know that, but for typing speed sake, the letter "5" is much easier! |
Renmoo (66) | ||
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