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| Thread ID: 111753 | 2010-08-10 07:13:00 | Chemistry Help! | xyz823 (13649) | PC World Chat |
| Post ID | Timestamp | Content | User | ||
| 1126326 | 2010-08-10 07:13:00 | Trying to work out the following question. Need balanced half equations, fully balanced redox equations and what would be observed. A freshly prepared solution of sodium hydrogen sulfite is added to a solution on iron (III) chloride. TIA |
xyz823 (13649) | ||
| 1126327 | 2010-08-10 07:35:00 | A freshly prepared solution of sodium hydrogen sulfite is added to a solution on iron (III) chloride. That's a question? Looks like statement to me..... |
pctek (84) | ||
| 1126328 | 2010-08-10 07:37:00 | It might help if you put any workings you have so far - otherwise you're likely to get whacked with the DYOFH stick! :thumbs: |
nofam (9009) | ||
| 1126329 | 2010-08-10 07:39:00 | Fe^3+ + e^- ---> Fe^2+ HSO3^- + H2O ---> SO4^2- + 3H+ + 2e^- I'm sure you know what to do from here. |
Renmoo (66) | ||
| 1126330 | 2010-08-10 07:40:00 | Final answer that I've got: 2Fe3+ + HSO3- + H2O ----> 2Fe2+ + SO42- + 3H+ + 2e- |
Renmoo (66) | ||
| 1126331 | 2010-08-10 07:43:00 | H2O + HSO3 (-1) -2e = SO4 (-2) + 3H(+1) Fe (+3) + e = Fe(+2) H20 + HSO3 + 2 Fe (+3) = SO4 (-2) + 2Fe(+2) + 3H(+1) Colour change from yellow/brown to pale green My chemistry is a little rusty though... |
user (1404) | ||
| 1126332 | 2010-08-10 07:48:00 | Cheers guys, just wasn't sure what was actually being reduced and what was being oxidised! Got myself all confused :/ | xyz823 (13649) | ||
| 1126333 | 2010-08-10 07:49:00 | Final answer that I've got: 2Fe3+ + HSO3- + H2O ----> 2Fe2+ + SO42- + 3H+ + 2e- You don't have any free electrons in a balanced redox equation! |
user (1404) | ||
| 1126334 | 2010-08-10 07:52:00 | It's been 55 years since I did any chemistry, but I'm wondering where did the Sodium go to ? NaHS03 | Terry Porritt (14) | ||
| 1126335 | 2010-08-10 08:01:00 | It's been 55 years since I did any chemistry, but I'm wondering where did the Sodium go to ? NaHS03 Sodium is a spectator ion and takes no part in the reaction. You can add them onto both sides of the equation if you like but it is not necessary in a redox equation. It is the same for the chloride ions. |
user (1404) | ||
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