| Forum Home | ||||
| PC World Chat | ||||
| Thread ID: 111753 | 2010-08-10 07:13:00 | Chemistry Help! | xyz823 (13649) | PC World Chat |
| Post ID | Timestamp | Content | User | ||
| 1126336 | 2010-08-10 08:03:00 | You don't have any free electrons in a balanced redox equation! Sans the electrons lol. Well spotted, thanks :) |
Renmoo (66) | ||
| 1126337 | 2010-08-10 08:06:00 | H2O + HSO3 (-1) -2e = SO4 (-2) + 3H(+1) Fe (+3) + e = Fe(+2) H20 + HSO3 + 2 Fe (+3) = SO4 (-2) + 2Fe(+2) + 3H(+1) Colour change from yellow/brown to pale green My chemistry is a little rusty though... Correct me if I'm wrong but, Don't you add electrons on to the left hand side of one half equation and add electrons the the right hand side of the other one? Meaning you would have to leave the hydrogen out giving this... SO3 (-1) + H2O = SO4 (-2) + 2H (+1) + e Fe (+3) + e = Fe (+2) SO3 (-1) + H2O + Fe (+3) = SO4 (-2) + 2H (+1) + Fe (+2) If I'm wrong don't hesitate to correct me! |
xyz823 (13649) | ||
| 1126338 | 2010-08-10 08:10:00 | SO3 (-1) + H2O = SO4 (-2) + 2H (+1) + e It is HSO3(-1) The hydrogen is part of the entity. Na+ is left out. |
Renmoo (66) | ||
| 1126339 | 2010-08-10 08:15:00 | Correct me if I'm wrong but, Don't you add electrons on to the left hand side of one half equation and add electrons the the right hand side of the other one? Meaning you would have to leave the hydrogen out giving this... SO3 (-1) + H2O = SO4 (-2) + 2H (+1) + e Fe (+3) + e = Fe (+2) SO3 (-1) + H2O + Fe (+3) = SO4 (-2) + 2H (+1) + Fe (+2) If I'm wrong don't hesitate to correct me! You have mistakenly written the bisulphite ion as SO3- instead of HSO3- This accounts for the 3H+ on the RHS. It does not matter whether you have electrons added on the left and right of the respective half reactions, it is the same overall if you subtract them from the half equation showing the oxidation. As long as everything balances in the end (like an algebra equation). |
user (1404) | ||
| 1126340 | 2010-08-10 08:15:00 | SO3 (-1) + H2O = SO4 (-2) + 2H (+1) + e It is HSO3(-1) The hydrogen is part of the entity. Na+ is left out. Ohk. Pretty sure I get it. |
xyz823 (13649) | ||
| 1126341 | 2010-08-10 19:56:00 | Once again we need to salute the collective wisdom of those haunting these forums. For me this has served as a reminder of what a nightmare I found chemistry, and of how much I've forgotten over the last 25 years. I was at a loss to post anything useful, and probably would still have struggled to answer this 25 years ago when the teaching was still fresh in my mind. |
Paul.Cov (425) | ||
| 1126342 | 2010-08-10 20:23:00 | B*gger. Saw this question and thought "hmmmm, should be easy meat" because one of my majors at Uni was Chemistry. Suffering succotash, I could not remember a frickin thing - 'tis probably true what they say, use it or lose it. sarel |
sarel (2490) | ||
| 1126343 | 2010-08-10 21:46:00 | www.studyit.org.nz Great website that I use to frequent every half a day five years ago. The tutors over there > my teachers in high school. Especially with Biology :stare: |
Renmoo (66) | ||
| 1126344 | 2010-08-10 21:47:00 | www.studyit.org.nz Great website that I use to frequent every half a day five years ago. The tutors over there > my teachers in high school. |
Renmoo (66) | ||
| 1126345 | 2010-08-10 22:06:00 | Must admit I struggled working through the question, but been early 80's since I graduated in chemistry. I recall the charge transfer transition state? and/or ligand field theory that causes the colour change? I also thought that double arrows are used for equilibrium rather than the = sign? Because Cl and Na are present what prevents (or could induce) them from precipitating/forming a salt solution? |
kahawai chaser (3545) | ||
| 1 2 3 4 | |||||