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| Thread ID: 50794 | 2004-11-02 00:18:00 | OT homework help | veterannz (960) | Press F1 |
| Post ID | Timestamp | Content | User | ||
| 286906 | 2004-11-02 01:30:00 | The first step is to simplify the quadratic in the top line (numerator): The coefficient of X2 (the number in front of the X2) is 1, which means we can try doing it the simple way: find two numbers that add to give the constant term (that is the 15), and multiply to give the coefficient of the X term (that is the 8). ie: 2 numbers that multiply to give 15 and add to give 8. +5 and +3 spring to mind. Thus we can simplify the numerator to (X+5).(X+3) The '.' means 'multiplied by' Because we have an (X+5) in the numerator and the denominator (the bottom of the fraction), we can cancel them out. That's because we can re-write the fraction as: (X+5) + (X+3) = (X+3) ------ (X+5) and there's your answer :) hope this helps, darren |
Spartacus (3313) | ||
| 286907 | 2004-11-02 02:08:00 | > (X+5) + (X+3) = (X+3) > ------ > (X+5) Sorry that should be (X+5) * (X+3) = (X+3) ------ (X+5) |
Spartacus (3313) | ||
| 286908 | 2004-11-02 02:42:00 | X2 + 8 X +15 -------------------- X + 5 = (X + 5) * (X + 3) -------------------- (X + 5) = (X + 3) = X + 3 |
andrew93 (249) | ||
| 286909 | 2004-11-02 02:43:00 | Bloody hell, how's that lot gonna help you work out if the shopkeeper gave you the right change for a loaf of bread. | 45South (4769) | ||
| 286910 | 2004-11-02 03:12:00 | > Bloody hell, how's that lot gonna help you work out > if the shopkeeper gave you the right change for a > loaf of bread. Change for bread was Form 1 - this'll let you know whether the structural supports of the shopkeeper's shelves will sufficiently support the weight of the bread ;) darren |
Spartacus (3313) | ||
| 286911 | 2004-11-02 03:17:00 | >Change for bread was Form 1 - this'll let you know whether the structural supports of the shopkeeper's shelves will sufficiently support the weight of the bread lol |
45South (4769) | ||
| 286912 | 2004-11-02 03:39:00 | LOL many thanks to all the contributors. My daughter was able to relate the information supplied to a previous school lesson. Phew |
veterannz (960) | ||
| 286913 | 2004-11-02 03:45:00 | I wonder how i ever got thru Form 5, 6 or 7, or even Uni Stage 1 Calc or Stats :( | MartynC (5610) | ||
| 286914 | 2004-11-02 05:27:00 | sy u seem to be a math illeterate (sp?) I dont know if you've seen last years level 2 90284. But for anyone else heres a question. Please not im doing level 2 maths..so i only saw this first today, but I got it. ___________ tara has a rectangular lawn that is 11 m long and 8 m wide. The lawn is to be surrounded by a path. The width of the path on each side of the lawn is the same. The path has an area of 100m^2> Calculate the width of the path. _____________________ | ______________ | | | | | | | | | | | | | | | | | | |_____________ | | |____________________| Thats the idea..sorry about poorly drawn... But yeh calculate the width of the path around the lawn. |
MrBeef (342) | ||
| 286915 | 2004-11-02 05:29:00 | ok, that drawing completely f**ked up | MrBeef (342) | ||
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